table of integrals pdf

However, if the positions of several integrals coincide because they contain the same complicated function, these integrals are put in the position defined by the complexity of the second function. Z Z n+1 x 1 1 eax xn dx = , n 6= −1 dx = ln |ax ® and AP ® are trademarks registered and/or owned by the College Board, which is not affiliated with, and does not endorse, this site. /Filter /FlateDecode Therefore, the desired function is f(x)=1 4 Z cotxdx= ln sinx +C 8. Table of Integrals, Series, and Products Seventh Edition I.S. Z cosec2 xdx= cotx+C 11. Trig Integrals: Integrals involving sin(x) and cos(x): Integrals involving sec(x) and tan(x): 1. Table of Integrals . Use the Print item from the "Question Help" menu to get a better print-out. INTEGRAL CALCULUS - EXERCISES 42 Using the fact that the graph of f passes through the point (1,3) you get 3= 1 4 +2+2+C or C = − 5 4. Techniques of Integration Over the next few sections we examine some techniques that are frequently successful when seeking antiderivatives of functions. Table of Laplace Transforms f(t) L[f(t)] = F(s) 1 1 s (1) eatf(t) F(s a) (2) U(t a) e as s (3) f(t a)U(t a) e asF(s) (4) (t) 1 (5) (t stt 0) e 0 (6) tnf(t) ( 1)n dnF(s) dsn (7) f0(t) sF(s) f(0) (8) fn(t) snF(s) s(n 1)f(0) (fn 1)(0) (9) Z t 0 f(x)g(t x)dx F(s)G(s) (10) tn (n= 0;1;2;:::) n! Table of Integrals for inverse trig forms, exponential/logarithmic forms, . Purchase Table of Integrals, Series, and Products - 7th Edition. Second, we find a fast way to compute it. Purchase Table of Integrals, Series, and Products - 8th Edition. The clustrmap is periodically (and automatically) archived and its counters reset, so the total is smaller. Z sinxdx= cosx+C 5. Provided by the Academic Center for Excellence 3 Common Derivatives and Integrals 4. , 1 1 1 + ≠− + ∫ = + C n n u u du n n 5. The OpenStax name, OpenStax logo, OpenStax book Integrals containing two functions '1(x) and '2(x) are located in the division and order corresponding to the more complicated function of the two. In this section we’ve got the proof of several of the properties we saw in the Integrals Chapter as well as a couple from the Applications of Integrals Chapter. wolfram. com/ index. View Table of integrals.pdf from MA 3253 at Mississippi State University. If you are redistributing all or part of this book in a print format, 1 of It's a pity this book is no longer in print, but it is still worth taking the trouble to buy a used copy. 1. Table of Laplace Transforms f(t) L[f(t)] = F(s) 1 1 s (1) eatf(t) F(s a) (2) U(t a) e as s (3) f(t a)U(t a) e asF(s) (4) (t) 1 (5) (t stt 0) e 0 (6) tnf(t) ( 1)n dnF(s) dsn (7) f0(t) sF(s) f(0) (8) fn(t) snF(s) s(n 1)f(0) (fn 1)(0) (9) Z t 0 f(x)g(t x)dx F(s)G(s) (10) tn (n= 0;1;2;:::) n! Gradshteyn and I.M. The first and second parts of the book, just as many sections, were written so that they could be read independently from each other. Table of Integrals∗ Basic Forms Integrals with Logarithms √ x ax + bdx = Z Z 1 x dx = xn+1 n+1 Z 1 dx = ln For example, they can help you get More about Areas 50 2.2. ∫ = u +C u du ln 6. Z cotudu=ln|sinu|+C 8. Z cosxdx= sinx+C 6. www.mathportal.org 5. This eighth edition of the classic Gradshteyn and Ryzhik Table of Integrals, Series, and Products is a completely revised edition of what is universally acknowledged by mathematical and applied science users as the key reference work concerning integrals and special functions. An elliptic integral is any integral of the general form f(x)= A(x)+B(x) C(x)+D(x)! About me. For other types of functions, see lists of integrals jsp) • V. H. Moll, The Integrals in Gradshteyn and Ryzhik (http:/ / www. sn+1 (11) tx … Functions ∫sin cosxdx x= − ∫cos sinxdx x= − sin sin22 1 2 4 x ∫ xdx x= − cos sin22 1 2 4 x ∫ xdx x= + sin cos cos3 31 3 ∫ xdx x x= − cos sin sin3 31 3 ∫ xdx x x= − ln tan sin 2 dx x xdx x ∫ = ln tan Arc Length, Parametric Curves 57 2.4. Therefore, the desired function is f(x)=1 4 Table of Standard Integrals 1. (3x2 + 4)d dx {u} = 12 u.u d dx { 2 − 4x2 + 7x5} = 1 2 2 − 4x2 + 7x5 (−8x + 35x4) d dx {c} = 0 , c is a constant ddx {6} = 0 , since ≅ 3.14 is a constant. Do not forget to use these tables when you need to When looking at the THEORY, STANDARD INTEGRALS, AN-SWERS or TIPS pages, use the Back button (at the bottom of the page) to return to the exercises Use the solutions intelligently. Z sinudu= − cosu+C 5. This eighth edition of the classic Gradshteyn and Ryzhik Table of Integrals, Series, and Products is a completely revised edition of what is universally acknowledged by mathematical and applied science users as the key reference work concerning integrals and special functions. integrals are given, as well as tables of Laplace, Mellin, and other transforms, which are used in the book. © 1999-2020, Rice University. #ӻ�D�"$Ӧ�W��6dKa��e�π;N�2i����~�8�ϙ�.� ��AF1�"��;{��gW��ˌ3$|C�h����f����@xC $ pdf doc ; Integration Techniques - A collection of problems using various integration techniques. Numerical Integration 41 1.10. ISBN 9780123849335, 9780123849342 Integration Tables - Manipulate the integrand in order to use a formula in the table of integrals. Z cscucotudu= − cscu+C 12. Print Book & E-Book. Professor Department of Mathematics Computing Ph.D. u ddx {(x3 + 4x + 1)3/4} = 34 (x3 + 4x + 1)−1/4. Z secxdx= ln secx+tanx +C 12. Z tanxdx= ln cosx +C 7. Provided by the Academic Center for Excellence 3 Common Derivatives and Integrals 4. , 1 1 1 + ≠− + ∫ = + C n n u u du n n 5. Z Z Z Z Z Z Z Z Z Table of integrals Note: Integrating constant is omitted. Trig Integrals: Integrals involving sin(x) and cos(x): Integrals involving sec(x) and tan(x): 1. (A) The Power Rule : Examples : d dx {un} = nu n−1. Z cotxdx= ln sinx +C 8. Z e xdx= e +C 4. Z dx x = lnjxj+C 3. are licensed under a, Integration Formulas and the Net Change Theorem, Integrals Involving Exponential and Logarithmic Functions, Integrals Resulting in Inverse Trigonometric Functions, Volumes of Revolution: Cylindrical Shells, Integrals, Exponential Functions, and Logarithms, Parametric Equations and Polar Coordinates, https://openstax.org/books/calculus-volume-2/pages/1-introduction, https://openstax.org/books/calculus-volume-2/pages/a-table-of-integrals, Creative Commons Attribution 4.0 International License. The following is a list of integrals (antiderivative functions) of rational functions.Any rational function can be integrated by partial fraction decomposition of the function into a sum of functions of the form: (−), and + ((−) +).which can then be integrated term by term. The result of finding an indefinite integral is usually a function plus a constant of integration. This allows the reader to quickly get to the heart of the matter. Trigonometric Integrals and Trigonometric Substitutions 26 1.7. Advanced Placement ® and AP ® are trademarks registered and/or owned by the College Board, which is not affiliated with, and does not endorse, this site. Not to mention their servers gave up the ghost turned into Zombies on 25 March 2015 (Brains! >> tulane. Home Research Teaching Students CV Software Google scholar. Improper Integrals 46 Chapter 2. Applications of Integration 50 2.1. Unformatted text preview: Table of Integrals (page 1) ...Using the browser's print will lead to an undesirable print-out. We recommend using a Program Boise State University Boise, Idaho, USA gradywright@boisestate.edu . Z Z Z Z Z Z Z Z Z Table of integrals Note: Integrating constant is omitted. However, if the positions of several integrals coincide because they contain the same complicated function, these integrals are put in the position defined by the complexity of the second function. Applications of Integration 50 2.1. The integral tables are extensive and quite helpful; I agree that this is a must-have for physics majors. The key idea is to replace a double integral by two ordinary "single" integrals. Convert the remaining factors to cos( )x (using sin 1 cos22x x.) Textbook content produced by OpenStax is licensed under a %PDF-1.5 Z cosecxdx= ln cosecx cotx +C 13. As an Amazon associate we earn from qualifying purchases. OpenStax is part of Rice University, which is a 501(c)(3) nonprofit. This new edition contains many new results and corrections to the existing integrals. Unformatted text preview: Table of Integrals (page 2) ...Using the browser's print will lead to an undesirable print-out. It's a pity this book is no longer in print, but it is still worth taking the trouble to buy a used copy. Trigonometric Integrals and Trigonometric Substitutions 26 1.7. Unformatted text preview: Table of Integrals (page 1) ...Using the browser's print will lead to an undesirable print-out. View integral tables 5.pdf from MATH 2314 at University of Texas, Dallas. Z sec2 udu= tanu+C 13. Gradshteyn and Ryzhik (GR) is the informal name of a comprehensive table of integrals originally compiled by the Russian mathematicians I. S. Gradshteyn and I. M. Ryzhik. In mathematics, the definite integral: ∫ is the area of the region in the xy-plane bounded by the graph of f, the x-axis, and the lines x = a and x = b, such that area above the x-axis adds to the total, and that below the x-axis subtracts from the total.. The key idea is to replace a double integral by two ordinary "single" integrals. The integral table in the frame above was produced TeX4ht for MathJax using the command sh ./makejax.sh integral-table the configuration file here, and the shell scripts ht5mjlatex and makejax.sh © Sep 2, 2020 OpenStax. dZk� l}�����Q%PK�4�c(��^�8�pm�t�CM�à�! Print Book & E-Book. Integration using Tables and CAS 39 1.9. ©2005 BE Shapiro Page 3 This document may not be reproduced, posted or published without permission. There have been visitors to integral-table.com since 2004. Z dx a 2+x = 1 a tan 1 x a +C 9. sec2 xdx= tanx+C 10. x��\K���ﯘܸ�F��tJ�e�JQ�*��Ej�+��A��-�ߧ�yp���p%�t��$�t�� y�.��/g���/ξ{*�(�]\g�f�Ɍ��K�]\e���.Voo��K�b�����������x3�٭������������ǖ�ӳ!s�i����` �J�Ͼ���{aks������G4d!�F�c]Ȕ�5PȐ�1N2e�A��B4=��_Gf!�ѕ�'Zț� Kz)��� Ryzhik Alan Jeffrey, Editor University of Newcastle upon Tyne, England Daniel Zwillinger, Editor Rensselaer Polytechnic Institute, USA Translated from Russian by Scripta Technica, Inc. AMSTERDAM •BOSTON HEIDELBERG LONDON NEW YORK •OXFORD PARIS • SAN DIEGO Z tanudu=ln|secu|+C 7. Table of Integrals, Series, and Products Seventh Edition I.S. List of integrals of exponential functions 3 ( is the modified Bessel function of the first kind) References • Wolfram Mathematica Online Integrator (http:/ / integrals. Z eu du = eu +C 4. For other types of functions, see lists of integrals Section 7-5 : Proof of Various Integral Properties. Use the Print item from the "Question Help" menu to get a better print-out. then you must include on every physical page the following attribution: If you are redistributing all or part of this book in a digital format, Its full title today is Table of Integrals, Series, and Products.. �7�[RR'|Z��&���(�r�����O1���h�x���9�k��D(�hcL&�dN�e��%�]�8�gL����$� ���ݘ�\��;Kɭ�������. View Calc 2 TABLE OF INTEGRATION FORMULASwithlines.pdf from MATH 22 at Howard University. Z dx x = lnjxj+C 3. Purchase Table of Integrals, Series, and Products - 7th Edition. The integral tables are extensive and quite helpful; I agree that this is a must-have for physics majors. Volumes 52 2.3. Z cscudu=ln|cscu−cotu|+C 10. For example, faced with Z x10 dx sn+1 (11) tx … Functions ∫sin cosxdx x= − ∫cos sinxdx x= − sin sin22 1 2 4 x ∫ xdx x= − cos sin22 1 2 4 x ∫ xdx x= + sin cos cos3 31 3 ∫ xdx x x= − cos sin sin3 31 3 ∫ xdx x x= − ln tan sin 2 dx x xdx x ∫ = ln tan STANDARD INTEGRALS are provided. Integration using Tables and CAS 39 1.9. 1.5. 4.0 and you must attribute OpenStax. In this section we’ve got the proof of several of the properties we saw in the Integrals Chapter as well as a couple from the Applications of Integrals Chapter. Save a du x dx sin( ) ii. double integral gives us the volume under the surface z = f(x,y), just as a single integral gives the area under a curve. CHAPTER 14 Multiple Integrals 14.1 Double Integrals 4 This chapter shows how to integrate functions of two or more variables. 0.2 Evaluation of double integrals To evaluate a double integral we do it in stages, starting from the inside and working out, using our knowledge of the methods for single integrals… S(x) dx where A(x),B(x),C(x) and D(x) are polynomials in x and S(x) is a polynomial of degree 3 or 4. More about Areas 50 2.2. Math 22 7.5 TABLE OF INTEGRATION FORMULAS Inde…nite Integral Z Z Z Z Z Z Z Z Z Z Z Z Z Inde…nite STANDARD INTEGRALS are provided. Integrals of Trig. !��|�K`���c���e�1}����Cv_L[���həs�wڎhV+�=�U��|�(ӖM���j�}D�A�g�S������R|�y��\VyK=��+�2���(K�)�:�"�(FZ=]�Ϸ���ԩ��d Z e xdx= e +C 4. Volumes 52 2.3. �L*�R#=�"4!���>�$G�VT3YcJj�\���(uT����Z��\���1ˆK�,�v����}D�R��P�����)�;��y�JH���AF��5I%�m���̧{Q���SVLTϪN�Ӫ�S��S�`� ��%�f�; �����8�Ŵ���Q{��������{D�h:�k���� ��S�ciS���+!D�r)�jw�L�d+�xr�ڸnU��%Z�v5e6�ޑ�� �����EÅ/?�� Z secxdx= ln secx+tanx +C 12. Z 1 u du =ln|u|+C 3. Table of Integrals 1. 1.5. Except where otherwise noted, textbooks on this site This page lists some of the most common antiderivatives CHAPTER 14 Multiple Integrals 14.1 Double Integrals 4 This chapter shows how to integrate functions of two or more variables. Our mission is to improve educational access and learning for everyone. Z sinxdx= cosx+C 5. View Table of integrals.pdf from MA 3253 at Mississippi State University. citation tool such as, Authors: Gilbert Strang, Edwin “Jed” Herman. 1. First, a double integral is defined as the limit of sums. Program Boise State University Boise, Idaho, USA gradywright@boisestate.edu . ISBN 9780123736376, 9780080471112 About me. Creative Commons Attribution-NonCommercial-ShareAlike License 4.0 license. The following is a list of integrals (antiderivative functions) of rational functions.Any rational function can be integrated by partial fraction decomposition of the function into a sum of functions of the form: (−), and + ((−) +).which can then be integrated term by term. Integration is the basic operation in integral calculus.While differentiation has straightforward rules by which the derivative of a complicated function can be found by differentiating its simpler component functions, integration does not, so tables of known integrals are often useful. This book is Creative Commons Attribution-NonCommercial-ShareAlike License The first and second parts of the book, just as many sections, were written so that they could be read independently from each other. Numerical Integration 41 1.10. html) Table of Integrals . ∫e du =eu +C Example 2: Evaluate ∫( ) 4x2 −5x3 +12 dx To evaluate this problem, use the first four Integral Formulas. Save a du x dx sin( ) ii. If the power of the sine is odd and positive: Goal: ux cos i. First, a double integral is defined as the limit of sums. math. Professor Department of Mathematics Computing Ph.D. Table of Integrals for inverse trig forms, exponential/logarithmic forms, . www.mathportal.org 5. Z cosudu= sinu+C 6. Use the Print item from the "Question Help" menu to get a better print-out. 7 0 obj << Partial Fractions 32 1.8. stream %���� View integral tables.pdf from MATH 220 at University of Missouri, Kansas City. View integral tables 5.pdf from MATH 2314 at University of Texas, Dallas. Z xn dx= xn+1 n+1 +C (n6= 1) 2. Z cosecxdx= ln cosecx cotx +C 13. Integration Formulas PDF Download (Trig, Definite, Integrals, Properties) Integration Formulas PDF Download:- Hello friends, welcome to our website mynotesadda.com.Today our post is related to Maths topic, in this post we will provide you LInk to download all types of PDF … not be reproduced without the prior and express written consent of Rice University. View integral tables.pdf from MATH 220 at University of Missouri, Kansas City. MyNotesAdda.com is an online Educational Platform, where you can download free PDF for UPSC, SSC CGL, BANK, RAILWAYS, RRB NTPC, LIC AAO, and many other exams.Our Integration Formulas PDF Download (Trig, Definite, Integrals, Properties) is very Simple and Easy. 1. ∫undu=un+1n+1+C,n≠−1∫undu=un+1n+1+C,n≠−1, 5. ∫sinudu=−cosu+C∫sinudu=−cosu+C, 8. ∫csc2udu=−cotu+C∫csc2udu=−cotu+C, 9. ∫secutanudu=secu+C∫secutanudu=secu+C, 10. ∫cscucotudu=−cscu+C∫cscucotudu=−cscu+C, 11. ∫tanudu=ln|secu|+C∫tanudu=ln|secu|+C, 12. ∫cotudu=ln|sinu|+C∫cotudu=ln|sinu|+C, 13. ∫secudu=ln|secu+tanu|+C∫secudu=ln|secu+tanu|+C, 14. ∫cscudu=ln|cscu−cotu|+C∫cscudu=ln|cscu−cotu|+C, 15. ∫dua2−u2=sin−1ua+C∫dua2−u2=sin−1ua+C, 16. ∫dua2+u2=1atan−1ua+C∫dua2+u2=1atan−1ua+C, 17. ∫duuu2−a2=1asec−1ua+C∫duuu2−a2=1asec−1ua+C, 18. ∫sin2udu=12u−14sin2u+C∫sin2udu=12u−14sin2u+C, 19. ∫cos2udu=12u+14sin2u+C∫cos2udu=12u+14sin2u+C, 20. ∫tan2udu=tanu−u+C∫tan2udu=tanu−u+C, 21. ∫cot2udu=−cotu−u+C∫cot2udu=−cotu−u+C, 22. ∫sin3udu=−13(2+sin2u)cosu+C∫sin3udu=−13(2+sin2u)cosu+C, 23. ∫cos3udu=13(2+cos2u)sinu+C∫cos3udu=13(2+cos2u)sinu+C, 24. ∫tan3udu=12tan2u+ln|cosu|+C∫tan3udu=12tan2u+ln|cosu|+C, 25. ∫cot3udu=−12cot2u−ln|sinu|+C∫cot3udu=−12cot2u−ln|sinu|+C, 26. ∫sec3udu=12secutanu+12ln|secu+tanu|+C∫sec3udu=12secutanu+12ln|secu+tanu|+C, 27. ∫csc3udu=−12cscucotu+12ln|cscu−cotu|+C∫csc3udu=−12cscucotu+12ln|cscu−cotu|+C, 28. ∫sinnudu=−1nsinn−1ucosu+n−1n∫sinn−2udu∫sinnudu=−1nsinn−1ucosu+n−1n∫sinn−2udu, 29. ∫cosnudu=1ncosn−1usinu+n−1n∫cosn−2udu∫cosnudu=1ncosn−1usinu+n−1n∫cosn−2udu, 30. ∫tannudu=1n−1tann−1u−∫tann−2udu∫tannudu=1n−1tann−1u−∫tann−2udu, 31. ∫cotnudu=−1n−1cotn−1u−∫cotn−2udu∫cotnudu=−1n−1cotn−1u−∫cotn−2udu, 32. ∫secnudu=1n−1tanusecn−2u+n−2n−1∫secn−2udu∫secnudu=1n−1tanusecn−2u+n−2n−1∫secn−2udu, 33. ∫cscnudu=−1n−1cotucscn−2u+n−2n−1∫cscn−2udu∫cscnudu=−1n−1cotucscn−2u+n−2n−1∫cscn−2udu, 34. ∫sinausinbudu=sin(a−b)u2(a−b)−sin(a+b)u2(a+b)+C∫sinausinbudu=sin(a−b)u2(a−b)−sin(a+b)u2(a+b)+C, 35. ∫cosaucosbudu=sin(a−b)u2(a−b)+sin(a+b)u2(a+b)+C∫cosaucosbudu=sin(a−b)u2(a−b)+sin(a+b)u2(a+b)+C, 36. ∫sinaucosbudu=−cos(a−b)u2(a−b)−cos(a+b)u2(a+b)+C∫sinaucosbudu=−cos(a−b)u2(a−b)−cos(a+b)u2(a+b)+C, 37. ∫usinudu=sinu−ucosu+C∫usinudu=sinu−ucosu+C, 38. ∫ucosudu=cosu+usinu+C∫ucosudu=cosu+usinu+C, 39. ∫unsinudu=−uncosu+n∫un−1cosudu∫unsinudu=−uncosu+n∫un−1cosudu, 40. ∫uncosudu=unsinu−n∫un−1sinudu∫uncosudu=unsinu−n∫un−1sinudu, 41. ∫sinnucosmudu=−sinn−1ucosm+1un+m+n−1n+m∫sinn−2ucosmudu=sinn+1ucosm−1un+m+m−1n+m∫sinnucosm−2udu∫sinnucosmudu=−sinn−1ucosm+1un+m+n−1n+m∫sinn−2ucosmudu=sinn+1ucosm−1un+m+m−1n+m∫sinnucosm−2udu, 42. ∫ueaudu=1a2(au−1)eau+C∫ueaudu=1a2(au−1)eau+C, 43. ∫uneaudu=1auneau−na∫un−1eaudu∫uneaudu=1auneau−na∫un−1eaudu, 44. ∫eausinbudu=eaua2+b2(asinbu−bcosbu)+C∫eausinbudu=eaua2+b2(asinbu−bcosbu)+C, 45. ∫eaucosbudu=eaua2+b2(acosbu+bsinbu)+C∫eaucosbudu=eaua2+b2(acosbu+bsinbu)+C, 46. ∫lnudu=ulnu−u+C∫lnudu=ulnu−u+C, 47. ∫unlnudu=un+1(n+1)2[(n+1)lnu−1]+C∫unlnudu=un+1(n+1)2[(n+1)lnu−1]+C, 48. ∫1ulnudu=ln|lnu|+C∫1ulnudu=ln|lnu|+C, 51. ∫tanhudu=lncoshu+C∫tanhudu=lncoshu+C, 52. ∫cothudu=ln|sinhu|+C∫cothudu=ln|sinhu|+C, 53. ∫sechudu=tan−1|sinhu|+C∫sechudu=tan−1|sinhu|+C, 54. ∫cschudu=ln|tanh12u|+C∫cschudu=ln|tanh12u|+C, 55. ∫sech2udu=tanhu+C∫sech2udu=tanhu+C, 56. ∫csch2udu=−cothu+C∫csch2udu=−cothu+C, 57. ∫sechutanhudu=−sechu+C∫sechutanhudu=−sechu+C, 58. ∫cschucothudu=−cschu+C∫cschucothudu=−cschu+C, 59. ∫sin−1udu=usin−1u+1−u2+C∫sin−1udu=usin−1u+1−u2+C, 60. ∫cos−1udu=ucos−1u−1−u2+C∫cos−1udu=ucos−1u−1−u2+C, 61. ∫tan−1udu=utan−1u−12ln(1+u2)+C∫tan−1udu=utan−1u−12ln(1+u2)+C, 62. ∫usin−1udu=2u2−14sin−1u+u1−u24+C∫usin−1udu=2u2−14sin−1u+u1−u24+C, 63. ∫ucos−1udu=2u2−14cos−1u−u1−u24+C∫ucos−1udu=2u2−14cos−1u−u1−u24+C, 64. ∫utan−1udu=u2+12tan−1u−u2+C∫utan−1udu=u2+12tan−1u−u2+C, 65. ∫unsin−1udu=1n+1[un+1sin−1u−∫un+1du1−u2],n≠−1∫unsin−1udu=1n+1[un+1sin−1u−∫un+1du1−u2],n≠−1, 66. ∫uncos−1udu=1n+1[un+1cos−1u+∫un+1du1−u2],n≠−1∫uncos−1udu=1n+1[un+1cos−1u+∫un+1du1−u2],n≠−1, 67. ∫untan−1udu=1n+1[un+1tan−1u−∫un+1du1+u2],n≠−1∫untan−1udu=1n+1[un+1tan−1u−∫un+1du1+u2],n≠−1, 68. ∫a2+u2du=u2a2+u2+a22ln(u+a2+u2)+C∫a2+u2du=u2a2+u2+a22ln(u+a2+u2)+C, 69. ∫u2a2+u2du=u8(a2+2u2)a2+u2−a48ln(u+a2+u2)+C∫u2a2+u2du=u8(a2+2u2)a2+u2−a48ln(u+a2+u2)+C, 70. ∫a2+u2udu=a2+u2−aln|a+a2+u2u|+C∫a2+u2udu=a2+u2−aln|a+a2+u2u|+C, 71. ∫a2+u2u2du=−a2+u2u+ln(u+a2+u2)+C∫a2+u2u2du=−a2+u2u+ln(u+a2+u2)+C, 72. ∫dua2+u2=ln(u+a2+u2)+C∫dua2+u2=ln(u+a2+u2)+C, 73. ∫u2dua2+u2=u2(a2+u2)−a22ln(u+a2+u2)+C∫u2dua2+u2=u2(a2+u2)−a22ln(u+a2+u2)+C, 74. ∫duua2+u2=−1aln|a2+u2+au|+C∫duua2+u2=−1aln|a2+u2+au|+C, 75. ∫duu2a2+u2=−a2+u2a2u+C∫duu2a2+u2=−a2+u2a2u+C, 76. ∫du(a2+u2)3/2=ua2a2+u2+C∫du(a2+u2)3/2=ua2a2+u2+C, 77. ∫u2−a2du=u2u2−a2−a22ln|u+u2−a2|+C∫u2−a2du=u2u2−a2−a22ln|u+u2−a2|+C, 78. ∫u2u2−a2du=u8(2u2−a2)u2−a2−a48ln|u+u2−a2|+C∫u2u2−a2du=u8(2u2−a2)u2−a2−a48ln|u+u2−a2|+C, 79. ∫u2−a2udu=u2−a2−acos−1a|u|+C∫u2−a2udu=u2−a2−acos−1a|u|+C, 80. ∫u2−a2u2du=−u2−a2u+ln|u+u2−a2|+C∫u2−a2u2du=−u2−a2u+ln|u+u2−a2|+C, 81. ∫duu2−a2=ln|u+u2−a2|+C∫duu2−a2=ln|u+u2−a2|+C, 82. ∫u2duu2−a2=u2u2−a2+a22ln|u+u2−a2|+C∫u2duu2−a2=u2u2−a2+a22ln|u+u2−a2|+C, 83. ∫duu2u2−a2=u2−a2a2u+C∫duu2u2−a2=u2−a2a2u+C, 84. ∫du(u2−a2)3/2=−ua2u2−a2+C∫du(u2−a2)3/2=−ua2u2−a2+C, 85. ∫a2−u2du=u2a2−u2+a22sin−1ua+C∫a2−u2du=u2a2−u2+a22sin−1ua+C, 86. ∫u2a2−u2du=u8(2u2−a2)a2−u2+a48sin−1ua+C∫u2a2−u2du=u8(2u2−a2)a2−u2+a48sin−1ua+C, 87. ∫a2−u2udu=a2−u2−aln|a+a2−u2u|+C∫a2−u2udu=a2−u2−aln|a+a2−u2u|+C, 88. ∫a2−u2u2du=−1ua2−u2−sin−1ua+C∫a2−u2u2du=−1ua2−u2−sin−1ua+C, 89. ∫u2dua2−u2=−u2a2−u2+a22sin−1ua+C∫u2dua2−u2=−u2a2−u2+a22sin−1ua+C, 90. ∫duua2−u2=−1aln|a+a2−u2u|+C∫duua2−u2=−1aln|a+a2−u2u|+C, 91. ∫duu2a2−u2=−1a2ua2−u2+C∫duu2a2−u2=−1a2ua2−u2+C, 92. ∫(a2−u2)3/2du=−u8(2u2−5a2)a2−u2+3a48sin−1ua+C∫(a2−u2)3/2du=−u8(2u2−5a2)a2−u2+3a48sin−1ua+C, 93. ∫du(a2−u2)3/2=ua2a2−u2+C∫du(a2−u2)3/2=ua2a2−u2+C, 94. ∫2au−u2du=u−a22au−u2+a22cos−1(a−ua)+C∫2au−u2du=u−a22au−u2+a22cos−1(a−ua)+C, 95. ∫du2au−u2=cos−1(a−ua)+C∫du2au−u2=cos−1(a−ua)+C, 96. ∫u2au−u2du=2u2−au−3a262au−u2+a32cos−1(a−ua)+C∫u2au−u2du=2u2−au−3a262au−u2+a32cos−1(a−ua)+C, 97. ∫duu2au−u2=−2au−u2au+C∫duu2au−u2=−2au−u2au+C, 98. ∫udua+bu=1b2(a+bu−aln|a+bu|)+C∫udua+bu=1b2(a+bu−aln|a+bu|)+C, 99. ∫u2dua+bu=12b3[(a+bu)2−4a(a+bu)+2a2ln|a+bu|]+C∫u2dua+bu=12b3[(a+bu)2−4a(a+bu)+2a2ln|a+bu|]+C, 100. ∫duu(a+bu)=1aln|ua+bu|+C∫duu(a+bu)=1aln|ua+bu|+C, 101. ∫duu2(a+bu)=−1au+ba2ln|a+buu|+C∫duu2(a+bu)=−1au+ba2ln|a+buu|+C, 102. ∫udu(a+bu)2=ab2(a+bu)+1b2ln|a+bu|+C∫udu(a+bu)2=ab2(a+bu)+1b2ln|a+bu|+C, 103. ∫uduu(a+bu)2=1a(a+bu)−1a2ln|a+buu|+C∫uduu(a+bu)2=1a(a+bu)−1a2ln|a+buu|+C, 104. ∫u2du(a+bu)2=1b3(a+bu−a2a+bu−2aln|a+bu|)+C∫u2du(a+bu)2=1b3(a+bu−a2a+bu−2aln|a+bu|)+C, 105. ∫ua+budu=215b2(3bu−2a)(a+bu)3/2+C∫ua+budu=215b2(3bu−2a)(a+bu)3/2+C, 106. ∫udua+bu=23b2(bu−2a)a+bu+C∫udua+bu=23b2(bu−2a)a+bu+C, 107. ∫u2dua+bu=215b3(8a2+3b2u2−4abu)a+bu+C∫u2dua+bu=215b3(8a2+3b2u2−4abu)a+bu+C, 108. ∫duua+bu=1aln|a+bu−aa+bu+a|+C,ifa>0=2−atan−1a+bu−a+C,ifa<0∫duua+bu=1aln|a+bu−aa+bu+a|+C,ifa>0=2−atan−1a+bu−a+C,ifa<0, 109. ∫a+buudu=2a+bu+a∫duua+bu∫a+buudu=2a+bu+a∫duua+bu, 110. ∫a+buu2du=−a+buu+b2∫duua+bu∫a+buu2du=−a+buu+b2∫duua+bu, 111. ∫una+budu=2b(2n+3)[un(a+bu)3/2−na∫un−1a+budu]∫una+budu=2b(2n+3)[un(a+bu)3/2−na∫un−1a+budu], 112. ∫undua+bu=2una+bub(2n+1)−2nab(2n+1)∫un−1dua+bu∫undua+bu=2una+bub(2n+1)−2nab(2n+1)∫un−1dua+bu, 113. ∫duuna+bu=−a+bua(n−1)un−1−b(2n−3)2a(n−1)∫duun−1a+bu∫duuna+bu=−a+bua(n−1)un−1−b(2n−3)2a(n−1)∫duun−1a+bu. 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